ABC26GN0797 · Decimal Fractions
Subject: General Aptitude · Chapter: Decimal Fractions · Exam: 2015 · Marks: · Difficulty:
Solve $4 \frac{2}{3}+3 \frac{1}{2}-1 \frac{2}{3}=$ ?
(a)$2 \frac{1}{5}$
(b)$2 \frac{5}{3}$
(c)$1 \frac{3}{4}$
(d)$1 \frac{1}{2}$
(e)$6 \frac{1}{2}$
Answer
Explanation
Given $4 \frac{2}{3}+3 \frac{1}{2}+1 \frac{2}{3}$ $$=\frac{14}{3}+\frac{7}{2}-\frac{5}{3}$$By taking LCM of 3, 2 and 3 is 6. $$\begin{aligned} & =\frac{28+21-10}{6} \\ & =\frac{39}{6}=\frac{13}{2}=6 \frac{1}{2} \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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