√(4/3)-√(3/4)= ? · ABC26GN1390

Subject: General Aptitude · Chapter: Square Roots and Cube Roots

$\sqrt{\frac{4}{3}}-\sqrt{\frac{3}{4}}=$ ?
(a)$\frac{4 \sqrt{3}}{6}$
(b)$\frac{1}{2 \sqrt{3}}$
(c)1
(d)$-\frac{1}{2 \sqrt{3}}$ (R.R.B., 2005)
Answer
Answer (as printed): B
Explanation
$\sqrt{\frac{4}{3}}-\sqrt{\frac{3}{4}}=\frac{\sqrt{4}}{\sqrt{3}}-\frac{\sqrt{3}}{\sqrt{4}}=\frac{\sqrt{4} \times \sqrt{4}-\sqrt{3} \times \sqrt{3}}{\sqrt{12}}=\frac{4-3}{2 \sqrt{3}}=\frac{1}{2 \sqrt{3}}$.

Explanation as extracted from the printed page; notation may be imperfect.

Study loop for Square Roots and Cube Roots

1. Practise the PYQsPrevious-year questions, with answers

· Browse this chapter in the app