Subject: General Aptitude · Chapter: Problems on Ages · Exam: 2009 · Marks: · Difficulty:
The ages of two persons differ by 16 years. If 6 years ago, the elder one be three times as old as the younger one, find their present ages.
Answer
Answer (as printed):
Explanation
Let their ages be x years and (x – 16) years. Then, (x – 6) = 3 {(x – 16) – 6} ⇒ x – 6 = 3 (x – 22) ⇒ 3x – x = 66 – 6 ⇒ 2x = 60 ⇒ x = 30. So, their ages are 30 years and (30 – 16) = 14 years.
Explanation as extracted from the printed page; notation may be imperfect.