The ages of two persons differ by 16 years. If 6 years ago, the elder one be three times as old as the… · ABC26GN1807
Subject: General Aptitude · Chapter: Problems on Ages · Exam: L.I.C. 2009
The ages of two persons differ by 16 years. If 6 years ago, the elder one be three times as old as the younger one, find their present ages.
Answer
No answer key was printed for this question.
Explanation
Let their ages be x years and (x – 16) years. Then, (x – 6) = 3 {(x – 16) – 6} ⇒ x – 6 = 3 (x – 22) ⇒ 3x – x = 66 – 6 ⇒ 2x = 60 ⇒ x = 30. So, their ages are 30 years and (30 – 16) = 14 years.
Explanation as extracted from the printed page; notation may be imperfect.