Subject: General Aptitude · Chapter: Problems on Ages · Exam: 2009 · Marks: · Difficulty:
The ratio of the ages of a father and his son is 17:7 respectively. Six years ago, the ratio of their ages was 3 : 1 respectively. What is the father's present age ?
(a)64 years
(b)51 years
(c)48 years
(d)Cannot be determined
(e)None of these
Answer
Answer (as printed): B
Explanation
Let father's age be $17 x$ years. Then, son's age $=7 x$ years. $$\begin{aligned} & \frac{17 x-6}{7 x-6}=\frac{3}{1} \Rightarrow 3(7 x-6)=17 x-6 \\ & \Rightarrow 21 x-18=17 x-6 \\ & \Rightarrow 4 x=12 \\ & \Rightarrow x=3 \end{aligned}$$ ∴ Father's present age $=17 x$ years $$=(17 \times 3) \text { years }=51 \text { years. }$$
Explanation as extracted from the printed page; notation may be imperfect.