ABC26GN2048 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: 2005 · Marks: · Difficulty:

What is the value of the following expression? $\log \left(\frac{9}{14}\right)-\log \left(\frac{15}{16}\right)+\log \left(\frac{35}{24}\right)$
(a)0
(b)1
(c)2
(d)3
Answer
Answer (as printed): A
Explanation
$$\begin{aligned} & \log \left(\frac{9}{14}\right)-\log \left(\frac{15}{16}\right)+\log \left(\frac{35}{24}\right) \\ & =\log \left(\frac{9}{14} \div \frac{15}{16} \times \frac{35}{24}\right)=\log \left(\frac{9}{14} \times \frac{16}{15} \times \frac{35}{24}\right)=\log 1=0 \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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