If log ₈ x+log ₈ 1/6=1/3, then the value of x is · ABC26GN2059

$$\begin{aligned} & \log _{8} x+\log _{8}\left(\frac{1}{6}\right)=\frac{1}{3} \\ & \Leftrightarrow \frac{\log x}{\log 8}+\frac{\log \frac{1}{6}}{\log 8}=\frac{1}{3} \Leftrightarrow \log x+\log \frac{1}{6}=\frac{1}{3} \log 8 \end{aligned}$$