ABC26GN2059 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:

If $\log _{8} x+\log _{8} \frac{1}{6}=\frac{1}{3}$, then the value of $x$ is
(a)12
(b)16
(c)18
(d)24
Answer
Answer (as printed): A
Explanation
$$\begin{aligned} & \log _{8} x+\log _{8}\left(\frac{1}{6}\right)=\frac{1}{3} \\ & \Leftrightarrow \frac{\log x}{\log 8}+\frac{\log \frac{1}{6}}{\log 8}=\frac{1}{3} \Leftrightarrow \log x+\log \frac{1}{6}=\frac{1}{3} \log 8 \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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