ABC26GN2060 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: 2005 · Marks: · Difficulty:

If $\log _{10} 125+\log _{10} 8=x$, then $x$ is equal to (M.B.A., 2005)
(a)$\frac{1}{3}$
(b).064
(c)-3
(d)3
Answer
Answer (as printed): D
Explanation
$\log _{10} 125+\log _{10} 8=x \Rightarrow \log _{10}(125 \times 8)=x$ $$\Rightarrow x=\log _{10}(1000)=\log _{10}(10)^{3}=3 \log _{10} 10=3 .$$

Explanation as extracted from the printed page; notation may be imperfect.

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