ABC26GN2087 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:

If $\log _{10} 2=0.3010$, the value of $\log _{10} 25$ is
(a)0.6020
(b)1.2040
(c)1.3980
(d)1.5050
Answer
Answer (as printed): C
Explanation
$$\begin{aligned} \log _{10} 25 & =\log _{10}\left(\frac{100}{4}\right)=\log _{10} 100-\log _{10} 4 \\ & =2-2 \log _{10} 2=(2-2 \times 0.3010) \\ & =(2-0.6020)=1.3980 \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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