ABC26GN2088 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:

If $\log _{10} 20=1.3010$ and $\log _{10} 30=1.4771$, then $\log _{10}$ (60000) is equal to
(a)0.7781
(b)1.7781
(c)2.7781
(d)4.7781
Answer
Answer (as printed): D
Explanation
$$\begin{aligned} \log _{10}(60000) & =\log _{10}(20 \times 30 \times 100)=\log _{10} 20+\log _{10} 30 \\ & =1.3010+1.4771+2=4.7781 . \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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