ABC26GN2092 · Logarithms
Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:
If $\log _{10} 2=0.3010$ and $\log _{10} 7=0.8451$, then the value of $\log _{10} 2.8$ is
(a)0.4471
(b)1.4471
(c)2.4471
(d)None of these
Answer
Explanation
$$\begin{aligned} \log _{10}(2.8)=\log _{10}( & \left.\frac{28}{10}\right)=\log _{10} 28-\log _{10} 10=\log _{10} \\ & \left(7 \times 2^{2}\right)-1=\log _{10} 7+2 \log _{10} 2-1 \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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