ABC26GN2091 · Logarithms

Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:

If $\log _{10} 2=0.3010$ and $\log _{10} 3=0.4771$, then the value of $\log _{10} 1.5$ is
(a)0.1761
(b)0.7116
(c)0.7161
(d)0.7611
Answer
Answer (as printed): A
Explanation
$$\log_{10}(1.5)=\log_{10}\left(\frac{3}{2}\right)=\log_{10}3-\log_{10}2=(0.4771-0.3010)=0.1761$$

Explanation as extracted from the printed page; notation may be imperfect.

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