ABC26GN2297 · Percentage

Subject: General Aptitude · Chapter: Percentage · Exam: 2009 · Marks: · Difficulty:

Two candidates fought an election. One of them got 62\% of the total votes and won by 432 votes. What is the total number of votes polled?
(a)1500
(b)1600
(c)1800
(d)Cannot be determined
(e)None of these
Answer
Answer (as printed): C
Explanation
Let the total number of votes polled be $x$. Then, votes polled by other candidate $=(100-62) \%$ of $x$ $=38 \%$ of $x$. $$\begin{array}{ll} \therefore & 62 \% \text { of } x-38 \% \text { of } x=432 \\ \Rightarrow & \frac{24 x}{100}=432 \Rightarrow x=\left(\frac{432 \times 100}{24}\right)=1800 . \end{array}$$

Explanation as extracted from the printed page; notation may be imperfect.

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