In a certain assembly constituency election, 80\% of voters exercised their voting right and the winning candidate got elected with $65 \%$ of votes polled. What percent of total votes did he poll?
(a)35
(b)52
(c)55
(d)57
Answer
Answer (as printed): B
Explanation
Let the total number of votes be $x$. Then, number of votes polled by wining candidate = 65\% of 80\% of $x$ $$=\left(\frac{65}{100} \times \frac{80}{100} \times x\right)=\frac{52 x}{100}=52 \% \text { of } x .$$ ∴ Required percentage $=52 \%$.
Explanation as extracted from the printed page; notation may be imperfect.