A monkey climbing up a pole ascends 6 metres and slips 3 metres in alternate minutes. If the pole is 60… · ABC26GN3614
Subject: General Aptitude · Chapter: Time and Distance · Exam: Campus Recruitment 2010
A monkey climbing up a pole ascends 6 metres and slips 3 metres in alternate minutes. If the pole is 60 metres high, how long will it take the monkey to reach the top?
(a)31 min
(b)33 min
(c)35 min
(d)37 min
Answer
Answer (as printed): D
Explanation
Net height ascended in 2 min $=(6-3) \mathrm{m}=3 \mathrm{m}$. Net height ascended in 36 min $=\left(\frac{3}{2} \times 36\right) \mathrm{m}=54 \mathrm{m}$. In the 37th min, the monkey ascends 6 m and reaches the top. Hence, total time taken $=37$ minutes.