Subject: General Aptitude · Chapter: Problems on Trains · Exam: · Marks: · Difficulty:
A train X starts from Meerut at 4 p.m. and reaches Ghaziabad at 5 p.m. while another train Y starts from Ghaziabad at 4 p.m. and reaches Meerut at 5.30 p.m. The two trains will cross each other at
(a)4.36 p.m.
(b)4.42 p.m.
(c)4.48 p.m.
(d)4.50 p.m.
Answer
Answer (as printed): A
Explanation
Suppose, the distance between Meerut and Ghaziabad is $x \mathrm{km}$. Time taken by $X$ to cover $x \mathrm{km}=1$ hour. Time taken by $Y$ to cover $x \mathrm{km}=\frac{3}{2}$ hours. $$\therefore \quad \text { Speed of } X=x \mathrm{kmph} \text {, Speed of } \mathrm{Y}=\left(\frac{2 x}{3}\right) \mathrm{kmph} \text {. }$$ Let them meet $y$ hours after 4 p.m. Then, $$\begin{aligned} & x y+\frac{2 x y}{3}=x \Leftrightarrow y\left(1+\frac{2}{3}\right)=1 \\ & \Leftrightarrow y=\frac{3}{5} \text { hours }=\left(\frac{3}{5} \times 60\right) \min =36 \mathrm{min} . \end{aligned}$$ So, the two trains meet at 4.36 p.m.