ABC26GN4803 · Volume and Surface Area
Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:
Find the length of the longest rod that can be placed in a room 16 m long, 12 m broad and $10 \frac{2}{3} \mathrm{m}$ high.
(a)$22 \frac{1}{3} \mathrm{m}$
(b)$22 \frac{2}{3} \mathrm{m}$
(c)23 m
(d)68 m
Answer
Explanation
Required length $$\begin{aligned} & =\sqrt{(16)^{2}+(12)^{2}+\left(\frac{32}{3}\right)^{2}} \mathrm{m}=\sqrt{256+144+\frac{1024}{9}} \mathrm{m} \\ = & \sqrt{\frac{4624}{9}} \mathrm{m}=\frac{68}{3} \mathrm{m}=22 \frac{2}{3} \mathrm{m} . \end{aligned}$$
Open in whiteboard · Browse this chapter in the app