ABC26GN4815 · Volume and Surface Area

Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: 2006 · Marks: · Difficulty:

A rectangular tank is 225 m by 162 m at the base. With what speed must water flow into it through an aperture 60 cm by 45 cm so that the level may be raised 20 cm in 5 hours?

(a)5000 m/hr

(b)5200 m/hr

(c)5400 m/hr

(d)5600 m/hr

Answer

Answer (as printed): C

Explanation

Volume flown in 5 hours $=\left(225 \times 162 \times \frac{20}{100}\right) \mathrm{m}^{3}=7290 \mathrm{m}^{3}$. $$\begin{aligned} & \text { Volume flown in } 1 \text { hour }=\left(\frac{7290}{5}\right) \mathrm{m}^{3}=1458 \mathrm{m}^{3} . \\ & \therefore \text { Required speed }=\left(\frac{1458}{0.60 \times 0.45}\right) \mathrm{m} / \mathrm{hr}=5400 \mathrm{m} / \mathrm{hr} . \end{aligned}$$

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