The dimensions of a certain machine are 48'' × 30'' × 52''. If the size of the machine is increased… · ABC26GN4835
Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: Campus Recruitment 2009
The dimensions of a certain machine are 48'' × 30'' × 52''. If the size of the machine is increased proportionately until the sum of its dimensions equals 156", what will be the increase in the shortest side?
(a)4''
(b)6"
(c)8''
(d)9"
Answer
Answer (as printed): B
Explanation
Sum of original dimensions $=48+30+52=130$. Increase in sum $=156-130=26$. Since the dimensions have been increased proportionately, $$\text { so increase in shortest side }=\left(26 \times \frac{30}{130}\right)^{\prime \prime}=6^{\prime \prime} \text {. }$$
Explanation as extracted from the printed page; notation may be imperfect.