Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:
If a metal slab of size $1 \mathrm{m} \times 20 \mathrm{cm} \times 1 \mathrm{cm}$ is melted to another slab of 1 mm thickness and 1 m width, then the length of the new slab thus formed will be
(a)200 cm
(b)400 cm
(c)600 cm
(d)1000 cm
Answer
Answer (as printed): A
Explanation
Let the length of the new slab be $x$ metres. Then, $1 \times 0.20 \times 0.01=x \times 0.001 \times 1 \Rightarrow x=\frac{0.002}{0.001}=2$. $$\text { ∴ } \text { Required length }=2 \mathrm{m}=200 \mathrm{cm} .$$