Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:
The dimensions of a piece of iron in the shape of a cuboid are 270 cm × 100 cm × 64 cm. If it is melted and recast into a cube, then the surface area of the cube will be
(a)$14400 \mathrm{cm}^{2}$
(b)$44200 \mathrm{cm}^{2}$
(c)$57600 \mathrm{cm}^{2}$
(d)$86400 \mathrm{cm}^{2}$
Answer
Answer (as printed): D
Explanation
Volume of the cube $=(270 \times 100 \times 64) \mathrm{cm}^{3}$. Edge of the cube = $$\sqrt[3]{270 \times 100 \times 64} \mathrm{cm}=(3 \times 10 \times 4) \mathrm{cm}=120 \mathrm{cm} \text {. }$$ ∴ Surface area $=(6 \times 120 \times 120) \mathrm{cm}^{2}=86400 \mathrm{cm}^{2}$.