In a simultaneous throw of two dice, what is the probability of getting a doublet? · ABC26GN5342
Subject: General Aptitude · Chapter: Probability
In a simultaneous throw of two dice, what is the probability of getting a doublet?
(a)$\frac{1}{6}$
(b)$\frac{1}{4}$
(c)$\frac{2}{3}$
(d)$\frac{3}{7}$
Answer
Answer (as printed): A
Explanation
In a simultaneous throw of two dice, $n(\mathrm{S})=(6 \times 6)=36$. Let $E=$ event of getting a doublet $=\{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)\}$. $$\therefore \quad P(E)=\frac{n(E)}{n(S)}=\frac{6}{36}=\frac{1}{6} .$$