Subject: General Aptitude · Chapter: Probability · Exam: · Marks: · Difficulty:
In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11 ?
(a)$\frac{1}{4}$
(b)$\frac{1}{6}$
(c)$\frac{7}{12}$
(d)$\frac{5}{36}$
Answer
Answer (as printed): D
Explanation
In a simultaneous throw of two dice, we have $n(S)=(6 \times 6)=36$. Let $E=$ event of getting a total of 10 or 11 $=\{(4,6),(5,5),(6,4),(5,6),(6,5)\}$. $\therefore n(E)=5$. $\therefore P(E)=\frac{n(E)}{n(S)}=\frac{5}{36}$.
Explanation as extracted from the printed page; notation may be imperfect.