The lowest energy state of a 1s¹ 2s¹ electronic configuration, according to hund's rule, is · ABC26IN0135

Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Electron Transfer Redox · Exam: CSIR NET 2018 · Marks: 2 · Difficulty: Medium

The lowest energy state of a $1s^{1}\,2s^{1}$ electronic configuration, according to hund's rule, is

(a)${}^{3}\mathrm{S}_{0}$

(b)${}^{1}\mathrm{S}_{0}$

(c)${}^{3}\mathrm{S}_{1}$

(d)${}^{1}\mathrm{S}_{1}$

Answer

Answer: C ✓ checked by 4AB · confidence high

Explanation

1s¹2s¹: parallel spins (S = 1) lie lowest — ³S₁ (c).

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