The correct molecular representation of W(Cp)₂(CO)₂ is (Cp=cyclopentadienyl) · ABC26IN0533
Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Cluster Compounds Wade Rules · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Easy
The correct molecular representation of $\mathrm{W}(\mathrm{Cp})_{2}(\mathrm{CO})_{2}$ is (Cp=cyclopentadienyl)
(a)$\left[\mathrm{W}\left(\eta^{1}-\mathrm{Cp}\right)\left(\eta^{3}-\mathrm{Cp}\right)(\mathrm{CO})_{2}\right]$
(b)$\left[\mathrm{W}\left(\eta^{1}-\mathrm{Cp}\right)\left(\eta^{5}-\mathrm{Cp}\right)(\mathrm{CO})_{2}\right]$
(c)$\left[\mathrm{W}\left(\eta^{3}-\mathrm{Cp}\right)\left(\eta^{5}-\mathrm{Cp}\right)(\mathrm{CO})_{2}\right]$
(d)$\left[\mathrm{W}\left(\eta^{5}-\mathrm{Cp}\right)_{2}(\mathrm{CO})_{2}\right]$
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
With two η⁵-Cp and two CO, W would have 6+10+4 = 20 electrons. One ring slips to η³, giving the 18-electron [W(η³-Cp)(η⁵-Cp)(CO)₂].
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