On reducing Fe₃(CO)₁₂ with an excess of sodium, a carbonylate ion is formed. The iron is isoelectronic with · ABC26IN1388
Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Cluster Compounds Wade Rules · Exam: CSIR NET DEC 2013 · Marks: 2 · Difficulty: Medium
On reducing $\mathrm{Fe}_{3}(\mathrm{CO})_{12}$ with an excess of sodium, a carbonylate ion is formed. The iron is isoelectronic with
(a)$\left[\mathrm{Mn}(\mathrm{CO})_{5}\right]^{-}$
(b)$\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]$
(c)$\left[\mathrm{Mn}(\mathrm{CO})_{5}\right]^{+}$
(d)$\left[\mathrm{V}(\mathrm{CO})_{6}\right]^{-}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Reduction gives [Fe(CO)₄]²⁻ (Collman's reagent), an 18-electron d¹⁰ species isoelectronic with Ni(CO)₄.
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