The oxidation state of molybdenum in [ (η⁷ -tropylium) Mo(CO)₃]⁺is: · ABC26IN1374

Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Exam: CSIR NET JUNE 2013 · Marks: 2 · Difficulty: Easy

The oxidation state of molybdenum in $\left[\left(\eta^{7} \text {-tropylium }\right) \mathrm{Mo}(\mathrm{CO})_{3}\right]^{+}$is:

(a)+2

(b)+1

(c)0

(d)-1

Answer

Answer: C ✓ checked by 4AB · confidence high

Explanation

Counting the tropylium ring as the aromatic C₇H₇⁺ cation (6 π electrons, L₃) and CO as neutral, the metal is Mo(0).

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