Question Bank › Inorganic Chemistry › Organometallic Compounds › ABC26IN0519The reaction of [Cp₂ TaMe₂] I (Cp=C₅ H₅⁻)with NaOMe yields. · ABC26IN0519 Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Easy
The reaction of $\left[\mathrm{Cp}_{2} \mathrm{TaMe}_{2}\right] \mathrm{I}\left(\mathrm{Cp}=\mathrm{C}_{5} \mathrm{H}_{5}^{-}\right)$with NaOMe yields.
(a) $\left[\mathrm{Cp}_{2} \mathrm{Ta}(\mathrm{OMe})_{2}\right] \mathrm{I}$
(b) $\left[\mathrm{Cp}_{2} \mathrm{Ta}(\mathrm{Me}) \mathrm{OMe}\right] \mathrm{I}$
(c) $\mathrm{Cp}_{2} \mathrm{Ta}(\mathrm{Me})=\mathrm{CH}_{2}$
(d) $\mathrm{Cp}_{2} \mathrm{Ta}(\mathrm{OMe})=\mathrm{CH}_{2}$
Answer Answer: C ✓ checked by 4AB · confidence high
Explanation Methoxide deprotonates a Ta–CH₃ of the cation, giving Schrock's methylidene Cp₂Ta(CH₃)(=CH₂) (c).
← Previous in chapter · Chapter list · Next in chapter → Study loop for Organometallic Compounds
Open in whiteboard · Browse this chapter in the app