ABC26PH0215 · Surface Chemistry
Subject: Physical Chemistry · Chapter: Surface Chemistry · Topic: Surface Chemistry – General · Exam: CSIR-NET JUNE 2015 · Marks: 2 · Difficulty: Medium
For a reaction on a surface 
At low pressure of H, the rate is proportional to
At low pressure of H, the rate is proportional to(a)$[H_{2}]$
(b)$1/[H_{2}]$
(c)$\left[\mathrm{H}_{2}\right]^{1 / 2}$
(d)$1/[H_{2}]^{1/2}$
Answer
SELF-PRACTICE — the source book printed no answer.
Nothing is invented here, so this question has no answer on record.
Explanation
$\theta=\dfrac{(kp)^{1/2}}{1+(kp)^{1/2}}$. At low P, $1 \gg (kP)^{1/2}$. $\theta \propto [H_{2}]^{1/2}$.