ABC26PH0389 · Electrochemistry

Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

Given that $\mathrm{E}_{0}\left(\mathrm{Fe}^{3+}, \mathrm{Fe}\right)=-0.04 \mathrm{V}$ and $\mathrm{E}_{0}\left(\mathrm{Fe}^{2+}, \mathrm{Fe}\right)=-0.44 \mathrm{V}$, the value of $\mathrm{E}_{0}\left(\mathrm{Fe}^{3+}, \mathrm{Fe}^{2+}\right)$ is:
(a)0.76 V
(b)-0.40 V
(c)-0.76 V
(d)0.40 V
Answer
SELF-PRACTICE — the source book printed no answer.

Nothing is invented here, so this question has no answer on record.

Explanation
No explanation was printed for this question.

Open in whiteboard · Browse this chapter in the app