For the reaction A + B → Z, the concentration of Z at time t is given by [Z] = [A]t=0(1 - e-kt) + [Z]t=0… · ABC26PH0678
Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Medium
For the reaction $\mathrm{A + B \rightarrow Z}$, the concentration of Z at time t is given by $[\mathrm{Z}] = [\mathrm{A}]_{t=0}(1 - e^{-kt}) + [\mathrm{Z}]_{t=0}$, where k is the rate constant. The rate law is:
(a)$-\frac{d[\;]}{dt} = k[\mathrm{A}]$
(b)$\frac{d[\;]}{dt} = k[\mathrm{A}]$
(c)$\frac{d[\;]}{dt} = k[\mathrm{Z}]$
(d)$\frac{d[\;]}{dt} = k[\mathrm{A}][\mathrm{B}]$
Answer
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