Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Exam: NET JUNE 2011 · Marks: 2 · Difficulty: Medium
The decomposition of gaseous acetaldehyde at T(K) follows second order kinetics. The half-life of this reaction is 400 s when the initial pressure is 250 Torr. What will be the rate constant (in $\mathrm{Torr}^{-1} \mathrm{s}^{-1}$ ) and half-life (in s ) respectively, if the initial pressure of the acetaldehyde is 200 Torr at the same temperature?
(a)$10^{5}$ and 500
(b)$10^{-5}$ and 400
(c)$10^{-4}$ and 400
(d)$10^{-5}$ and 500
Answer
SELF-PRACTICE — the source book printed no answer.
Nothing is invented here, so this question has no answer on record.