ABC26GN2090 · Logarithms
Subject: General Aptitude · Chapter: Logarithms · Exam: · Marks: · Difficulty:
If $\log _{10} 3=0.4771$ and $\log _{10} 7=0.8451$, then the value of $\log _{10}\left(23 \frac{1}{3}\right)$ is equal to
(a)0.368
(b)1.356
(c)1.368
(d)1.477
Answer
Explanation
$$\begin{aligned} & \log _{10}\left(23 \frac{1}{3}\right)=\log _{10}\left(\frac{70}{3}\right)=\log _{10} 70-\log _{10} 3=\log _{10} \\ & (7 \times 10)-\log _{10} 3 \\ & =\log _{10} 7+\log _{10} 10-\log _{10} 3=0.8451+1-0.4771=1.368 \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
Open in whiteboard · Browse this chapter in the app