ABC26GN2296 · Percentage

Subject: General Aptitude · Chapter: Percentage · Exam: 2009 · Marks: · Difficulty:

In an examination it is required to get 296 of the total maximum aggregate marks to pass. A student gets 259 marks and is decided failed. The difference of marks obtained by the student and that required to pass is 5\%. What are the maximum aggregate marks a student can get?
(a)690
(b)740
(c)780
(d)Cannot be determined
Answer
Answer (as printed): B
Explanation
Let the maximum marks be $x$. Then, $5 \%$ of $x=296-259 \Rightarrow \frac{5 x}{100}=37$ $$\Rightarrow \quad x=\left(\frac{37 \times 100}{5}\right)=740 .$$

Explanation as extracted from the printed page; notation may be imperfect.

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