Number System · General Aptitude

ABC26GN0179 · 8796 223+8796 77= ?

ABC26GN0180 · 287 287+269 269-2 287 269= ?

ABC26GN0181 · \(476+424)2-4 476 424 \= ?

ABC26GN0182 · The value of 112 54 is

ABC26GN0183 · Multiply 5746320819 by 125.

ABC26GN0184 · 935421 625= ?

ABC26GN0185 · (999)2-(998)2= ? · 2008

ABC26GN0186 · (80)2-(65)2+81= ?

ABC26GN0187 · (24+25+26)2-(10+20+25)2= ?

ABC26GN0188 · (65)2-(55)2= ?

ABC26GN0189 · If a and b be positive integers such that a2-b2=19, then the value of a is · 2010

ABC26GN0190 · If a and b are positive integers, a>b and (a+b)2- (a-b)2>29, then the smallest value of a is

ABC26GN0191 · 397 397+104 104+2 397 104= ?

ABC26GN0192 · If (64)2-(36)2=20 x, then x= ?

ABC26GN0193 · (489+375)2-(489-375)2(489 375)= ?

ABC26GN0196 · (854 854 854-276 276 276)/(854 854+854 276+276 276)= ?

ABC26GN0197 · (753 753+247 247-753 247)/(753 753 753+247 247 247)= ?

ABC26GN0198 · (256 256-144 144)/112 is equal to

ABC26GN0199 · If a=11 and b=9, then the value of (a2+b2+a ba3-b3 ) is · 2010

ABC26GN0200 · If a+b+c=0,(a+b)(b+c)(c+a) equals · 2005

ABC26GN0201 · If a=7, b=5, c=3, then the value of a2+b2+ c2-a b-b c-c a is

ABC26GN0202 · Both addition and multiplication of numbers are operations which are

ABC26GN0203 · Which of the following digits will replace the H marks in the following equation? 9 H+H 8+H 6=230

ABC26GN0204 · Find the missing number in the following addition problem:

ABC26GN0205 · What number should replace M in this multiplication problem?

ABC26GN0206 · If p and q represent digits, what is the maximum possible value of q in the statement (S.S.C., 2010) 5 p 9+327+2 q 8=1114 ?

ABC26GN0207 · What would be the maximum value of Q in the following equation? 5 P 7+8 Q 9+R 32=1928

ABC26GN0208 · What should be the maximum value of Q in the following equation? 5 P 9-7 Q 2+9 R 6=823

ABC26GN0209 · In the following sum, '?' stands for which digit? ? + 1? + 2? +? 3 +? 1 = 21?

ABC26GN0210 · B takes the value

ABC26GN0211 · C takes the value a sum which is greater than when it is multiplied

ABC26GN0212 · A 3-digit number 4 a 3 is added to another 3-digit number 984 to give the four-digit number 13b7, which is divisible by 11. Then, (a+b) is · 2006

ABC26GN0214 · * * * * × * 8 * * 1 In the above multiplication problem, * is equal to

ABC26GN0215 · If * means adding 6 times the second number to the first number, then (1 * 2) * 3 equals

ABC26GN0216 · If 1 × 2 × 3 × ........ × n is denoted by n , then little finger 5, then reversed direction, calling the 8 – 7 – 6 is equal to ring finger…

ABC26GN0217 · The highest power of 9 dividing 99! completely is

ABC26GN0218 · For an integer n, n!=n(n-1)(n-2) 3.2.1. (P.C.S., 2008) Then, 1!+2!+3!++100! when divided by 5 leaves remainder

ABC26GN0219 · The number of prime factors in the expression 610 717 1127 is equal to

ABC26GN0220 · What is the number of prime factors contained in the product 307 225 3411 ?

ABC26GN0221 · What number multiplied by 48 will give the same of (22 + 42 + 62 + .... + 402) is product as 173 multiplied by 240?

ABC26GN0222 · The value of 52+62+ .+102+202 is

ABC26GN0223 · Given that 1+2+3+4+ .+10=55, then the sum 6+12+18+24+ .+60 is equal to

ABC26GN0224 · If m and n are natural numbers such that 2m-2n= 960, what is the value of m ? · 2007

ABC26GN0225 · On multiplying a number by 7, all the digits in the product appear as 3's. The smallest such number is · 2006

ABC26GN0226 · The number of digits in the smallest number, which when multiplied by 7 yields all nines, is

ABC26GN0227 · A boy multiplies 987 by a certain number and obtains 559981 as his answer. If in the answer both 9's are wrong but the other digits are…

ABC26GN0228 · The numbers 1, 3, 5, ........., 25 are multiplied together. The number of zeros at the right end of the product is · 2006

ABC26GN0229 · The numbers 1, 2, 3, 4, 1000 are multiplied together. The number of zeros at the end (on the right) of the product must be

ABC26GN0230 · First 100 multiples of 10 i.e. 10, 20, 30, 1000 are multiplied together. The number of zeros at the end of the product will be

ABC26GN0231 · The number of zeros at the end of the product 5 10 15 20 25 30 35 40 45 50 is