General Aptitude

Number System

247 questions in this chapter, page 4 of 5.

Study loop for Number System

1. Practise the PYQsPrevious-year questions, with answers

General

ABC26GN0263 · Consider the following statements: The numbers 24984, 26784 and 28584 are (1) divisible by 3 (2) divisible by 4 (3) divisible by 9 Which of…
ABC26GN0264 · Which of the following numbers is a multiple of 8 ?
ABC26GN0265 · If 78*3945 is divisible by 11, where * is a digit, then * is equal to
ABC26GN0266 · If m and n are integers divisible by 5, which of the following is not necessarily true?
ABC26GN0268 · Which of the following numbers is divisible by 3, 7, 9 and 11?
ABC26GN0269 · A number 476**0 is divisible by both 3 and 11. The non-zero digits in the hundred's and ten's place respectively are
ABC26GN0271 · If the number 357*25* is divisible by both 3 and 5, then the missing digits in the unit's place and the thousandth's place respectively are
ABC26GN0272 · 6897 is divisible by
ABC26GN0273 · Which of the following numbers is exactly divisible by 24?
ABC26GN0274 · The number 311311311311311311311 is
ABC26GN0275 · 325325 is a six-digit number. It is divisible by
ABC26GN0276 · If the seven-figure number 30X0103 is a multiple of 13, then X is
ABC26GN0277 · If a number is divisible by both 11 and 13, then it must be necessarily
ABC26GN0279 · If x and y are two digits of the number 653 x y such that the number is divisible by 80, then x+y is equal to
ABC26GN0280 · The six-digit number 5 A B B 7 A is a multiple of 33 for non-zero digits A and B. Which of the following could be possible value of A+B ? · 2010
ABC26GN0281 · Which of the following numbers is divisible by 99?
ABC26GN0282 · The digits indicated by * in 3422213** so that this number is divisible by 99 are · 2010
ABC26GN0283 · If 37X3 is a four-digit natural number divisible by 7, then the place marked as X must have the value
ABC26GN0285 · If a number 774958A96B is divisible by 8 and 9, the respective values of A and B will be
ABC26GN0286 · How many of the following numbers are divisible by 132? 264, 396, 462, 792, 968, 2178, 5184, 6336
ABC26GN0287 · If x and y are positive integers such that (3 x+7 y) is a multiple of 11, then which of the following is also a multiple of 11?
ABC26GN0288 · If n be any natural number then by which largest number (n3-n) is always divisible? · 2010
ABC26GN0289 · If a and b are two odd positive integers, by which of the following integers is (a4-b4) always divisible? · 2010
ABC26GN0290 · The difference between the squares of any two consecutive integers is equal to
ABC26GN0291 · The number 6 n2+6 n for natural number n is always divisible by · 2007
ABC26GN0292 · The difference of a number consisting of two digits and the number formed by interchanging the digits is always divisible by
ABC26GN0293 · The sum of a number consisting of two digits and the number formed by interchanging the digits is always divisible by
ABC26GN0294 · The largest natural number, which exactly divides the product of any four consecutive natural numbers, is · 2007
ABC26GN0295 · If n is a whole number greater than 1, then n2 (n2-1) is always divisible by
ABC26GN0296 · If n is any odd number greater than 1, then n (n2-1) is
ABC26GN0297 · The sum of the digits of a 3-digit number is subtracted from the number. The resulting number is always
ABC26GN0298 · A number is multiplied by 11 and 11 is added to the product. If the resulting number is divisible by 13, the smallest original number is
ABC26GN0299 · The product of any three consecutive natural numbers is always divisible by
ABC26GN0300 · The sum of three consecutive odd numbers is always divisible by I. 2 II. 3 III. 5 IV. 6
ABC26GN0301 · The greatest number by which the product of three consecutive multiples of 3 is always divisible is
ABC26GN0302 · If p is a prime number greater than 3, then (p2-1) is always divisible by
ABC26GN0303 · The difference between the squares of two consecutive odd integers is always divisible by
ABC26GN0304 · A 4-digit number is formed by repeating a 2-digit number such as 2525, 3232 etc. Any number of this form is exactly divisible by · 2010
ABC26GN0305 · A 6-digit number is formed by repeating a 3-digit number; for example, 256256 or 678678 etc. Any number of this form is always exactly…
ABC26GN0306 · The sum of the digits of a natural number (10n-1) is 4707, where n is a natural number. The value of n is · 2010
ABC26GN0307 · (xn-an) is divisible by (x-a)
ABC26GN0308 · Which one of the following is the number by which the product of 8 consecutive integers is divisible?
ABC26GN0309 · Consider the following statements: For any positive integer n, the number 10n-1 is divisible by (1) 9 for n=odd only (2) 9 for n= even only…
ABC26GN0311 · If the square of an odd natural number is divided by 8, then the remainder will be
ABC26GN0313 · The difference of the squares of two consecutive even integers is divisible by
ABC26GN0314 · The difference of the squares of two consecutive odd integers is divisible by
ABC26GN0315 · The smallest 4-digit number exactly divisible by 7 is · 2009
ABC26GN0316 · What least number must be added to 1056 to get a number exactly divisible by 23? · 2009
ABC26GN0317 · Which of the following numbers should be added to 8567 to make it exactly divisible by 4? (Bank Recruitment, 2008) · 2008
ABC26GN0320 · The least number, which must be added to the greatest 6-digit number so that the sum may be exactly divisible by 327 is