Number System
247 questions in this chapter, page 3 of 5.
Study loop for Number System
1. Practise the PYQsPrevious-year questions, with answers
General
ABC26GN0176 · 107 × 107+93 × 93= ?
ABC26GN0177 · 217 × 217+183 × 183= ?
ABC26GN0178 · 106 × 106-94 × 94= ?
ABC26GN0179 · 8796 × 223+8796 × 77= ?
ABC26GN0180 · 287 × 287+269 × 269-2 × 287 × 269= ?
ABC26GN0181 · {(476+424)2-4 × 476 × 424}= ?
ABC26GN0183 · Multiply 5746320819 by 125.
ABC26GN0184 · 935421 × 625= ?
ABC26GN0189 · If a and b be positive integers such that a2-b2=19, then the value of a is · 2010
ABC26GN0190 · If a and b are positive integers, a>b and (a+b)2- (a-b)2>29, then the smallest value of a is
ABC26GN0191 · 397 × 397+104 × 104+2 × 397 × 104= ?
ABC26GN0192 · If (64)2-(36)2=20 × x, then x= ?
ABC26GN0193 · ((489+375)2-(489-375)2)/((489 × 375))= ?
ABC26GN0196 · (854 × 854 × 854-276 × 276 × 276)/(854 × 854+854 × 276+276 × 276)= ?
ABC26GN0197 · (753 × 753+247 × 247-753 × 247)/(753 × 753 × 753+247 × 247 × 247)= ?
ABC26GN0198 · (256 × 256-144 × 144)/112 is equal to
ABC26GN0199 · If a=11 and b=9, then the value of ((a2+b2+a b)/(a3-b3)) is · 2010
ABC26GN0201 · If a=7, b=5, c=3, then the value of a2+b2+ c2-a b-b c-c a is
ABC26GN0202 · Both addition and multiplication of numbers are operations which are
ABC26GN0206 · If p and q represent digits, what is the maximum possible value of q in the statement (S.S.C., 2010) 5 p 9+327+2 q 8=1114 ?
ABC26GN0207 · What would be the maximum value of Q in the following equation? 5 P 7+8 Q 9+R 32=1928
ABC26GN0208 · What should be the maximum value of Q in the following equation? 5 P 9-7 Q 2+9 R 6=823
ABC26GN0209 · In the following sum, '?' stands for which digit? ? + 1? + 2? +? 3 +? 1 = 21?
ABC26GN0212 · A 3-digit number 4 a 3 is added to another 3-digit number 984 to give the four-digit number 13b7, which is divisible by 11. Then, (a+b) is · 2006
ABC26GN0215 · If * means adding 6 times the second number to the first number, then (1 * 2) * 3 equals
ABC26GN0217 · The highest power of 9 dividing 99! completely is
ABC26GN0218 · For an integer n, n!=n(n-1)(n-2) … 3.2.1. (P.C.S., 2008) Then, 1!+2!+3!+…+100! when divided by 5 leaves remainder
ABC26GN0223 · Given that 1+2+3+4+….+10=55, then the sum 6+12+18+24+….+60 is equal to
ABC26GN0225 · On multiplying a number by 7, all the digits in the product appear as 3's. The smallest such number is · 2006
ABC26GN0226 · The number of digits in the smallest number, which when multiplied by 7 yields all nines, is
ABC26GN0227 · A boy multiplies 987 by a certain number and obtains 559981 as his answer. If in the answer both 9's are wrong but the other digits are…
ABC26GN0228 · The numbers 1, 3, 5,........., 25 are multiplied together. The number of zeros at the right end of the product is · 2006
ABC26GN0231 · The number of zeros at the end of the product 5 × 10 × 15 × 20 × 25 × 30 × 35 × 40 × 45 × 50 is
ABC26GN0232 · The number of zeros at the end of 60 ! is
ABC26GN0234 · The numbers 2, 4, 6, 8, ____ 98, 100 are multiplied together. The number of zeros at the end of the product must be
ABC26GN0235 · Let S be the set of prime numbers greater than or equal to 2 and less than 100. Multiply all the elements of S. With how many consecutive…
ABC26GN0241 · The unit's digit in the product 274 × 318 × 577 × 313 is
ABC26GN0243 · The digit in the unit place of the number represented by (795-358) is
ABC26GN0246 · The digit in the unit's place of the product (2464)1793 ×(615)317 ×(131)491 is
ABC26GN0251 · Let x be the product of two numbers 3,659,893,456,789,325,678 and 342,973,489,379,256. The number of digits in x is · 2010
ABC26GN0252 · Let a number of three digits have for its middle digit the sum of the other two digits. Then it is a multiple of · 2008
ABC26GN0253 · What least value must be given to n so that the number 6135 n 2 becomes divisible by 9 ? · 2008
ABC26GN0254 · Find the multiple of 11 in the following numbers. · 2006
ABC26GN0256 · Which of the following numbers is not divisible by 18?
ABC26GN0257 · The number 89715938* is divisible by 4. The unknown non-zero digit marked as * will be
ABC26GN0258 · Which one of the following numbers is divisible by 3?
ABC26GN0259 · A number is divisible by 11 if the difference between the sums of the digits in odd and even places respectively is
ABC26GN0260 · Which one of the following numbers is divisible by 11?
ABC26GN0261 · Which one of the following numbers is divisible by 15?
ABC26GN0262 · 7386038 is divisible by